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-7=-0.3x^2+3x+4
We move all terms to the left:
-7-(-0.3x^2+3x+4)=0
We get rid of parentheses
0.3x^2-3x-4-7=0
We add all the numbers together, and all the variables
0.3x^2-3x-11=0
a = 0.3; b = -3; c = -11;
Δ = b2-4ac
Δ = -32-4·0.3·(-11)
Δ = 22.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{22.2}}{2*0.3}=\frac{3-\sqrt{22.2}}{0.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{22.2}}{2*0.3}=\frac{3+\sqrt{22.2}}{0.6} $
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